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How do you solve #x^2+5x=0#?

Answer 1

Genesis Allen

The solutions are:
#color(blue)(x = 0#
#color(blue)(x= - 5 #

#x^2 + 5x = 0#

#x# is common to both terms of the expression.

#x ( x + 5) = 0#

To find the answers, equating the factors to zero:

#color(blue)(x = 0#

#x+5= 0 # #color(blue)(x= - 5 #

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Answer 2

Savannah Anderson

To solve the equation ( x^2 + 5x = 0 ), you can factor out ( x ) from both terms:

( x(x + 5) = 0 )

This equation is satisfied when either ( x = 0 ) or ( x + 5 = 0 ). Solving ( x + 5 = 0 ) gives ( x = -5 ). So, the solutions to the equation are ( x = 0 ) and ( x = -5 ).

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Answer 3

Kennedy Adams

To solve the equation (x^2 + 5x = 0), you can factor out the common factor (x), giving (x(x + 5) = 0). Then, set each factor equal to zero and solve for (x). So, (x = 0) or (x + 5 = 0). Solving the second equation yields (x = -5). Therefore, the solutions are (x = 0) and (x = -5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.