How do you solve # (x^2 - 5)/(x + 3) = 0#?
I found:
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To solve the equation (x^2 - 5)/(x + 3) = 0, we set the numerator equal to zero and solve for x.
x^2 - 5 = 0
Adding 5 to both sides:
x^2 = 5
Taking the square root of both sides:
x = ±√5
Therefore, the solutions to the equation are x = √5 and x = -√5.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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