How do you solve # x^2+4x-5=0 #?
Plug it in the equation:
and set equal to zero
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To solve the quadratic equation ( x^2 + 4x - 5 = 0 ), you can use the quadratic formula or factorization method.
Using the quadratic formula: [ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} ]
Where:
- ( a = 1 )
- ( b = 4 )
- ( c = -5 )
Substitute the values into the formula: [ x = \frac{{-4 \pm \sqrt{{4^2 - 4(1)(-5)}}}}{{2(1)}} ] [ x = \frac{{-4 \pm \sqrt{{16 + 20}}}}{{2}} ] [ x = \frac{{-4 \pm \sqrt{{36}}}}{{2}} ] [ x = \frac{{-4 \pm 6}}{{2}} ]
This gives two solutions: [ x_1 = \frac{{-4 + 6}}{{2}} = \frac{2}{2} = 1 ] [ x_2 = \frac{{-4 - 6}}{{2}} = \frac{{-10}}{2} = -5 ]
So, the solutions to the equation ( x^2 + 4x - 5 = 0 ) are ( x = 1 ) and ( x = -5 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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