How do you solve #x^2 +4x=21#?
By simple factorization. Failing that, by use of the quadratic formula.
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To solve the equation (x^2 + 4x = 21), you can follow these steps:
- Rewrite the equation in standard quadratic form: (x^2 + 4x - 21 = 0).
- Factor the quadratic expression: ((x + 7)(x - 3) = 0).
- Set each factor equal to zero and solve for (x): (x + 7 = 0 \rightarrow x = -7) and (x - 3 = 0 \rightarrow x = 3).
Therefore, the solutions to the equation are (x = -7) and (x = 3).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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