How do you solve #x^2 + 4x = 0# by completing the square?
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To solve the equation x^2 + 4x = 0 by completing the square, follow these steps:

Move the constant term to the other side of the equation: x^2 + 4x = 0 x^2 + 4x  0 = 0

Identify and halve the coefficient of the linear term (4x), then square it: (4/2)^2 = 4

Add the squared value obtained in step 2 to both sides of the equation: x^2 + 4x + 4 = 4

Rewrite the left side of the equation as a perfect square trinomial: (x + 2)^2 = 4

Take the square root of both sides and solve for x: x + 2 = ±√4 x + 2 = ±2 x = 2 ± 2

Solve for x: x = 2 + 2 = 0 x = 2  2 = 4
So, the solutions to the equation x^2 + 4x = 0 are x = 0 and x = 4.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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