How do you solve #x^2 – 3x = 4x – 1# using the quadratic formula?
To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0),To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0) To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), whichTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0) 2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0) 2.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifiesTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
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Combine likeTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms:To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x +To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x +To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0). To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0). 2.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0) To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
IdentifyTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0) 3.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficientsTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
IdentifyTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients:To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify theTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficientsTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (aTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (aTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1),To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (bTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1),To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (bTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7),To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), andTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7),To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (cTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (cTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1). To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1) To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1). 3To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1) 4.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula:To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \fracTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-bTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-bTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrtTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{bTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4acTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4acTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2aTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2aTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}). To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}) To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}). 4To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}) 5To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}). 4.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}) 5.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute theTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
PlugTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficientsTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug inTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients intoTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in theTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into theTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficientsTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formulaTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients:To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula:To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
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Plug in the coefficients: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \fracTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \fracTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
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Plug in the coefficients: (x = \frac{{-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
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Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
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Substitute the coefficients into the formula: (x = \frac{{-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
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Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
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Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7)To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7)To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}) To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}). To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}) 6.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}). 5To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
SimplTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
SimplTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
SimplifyTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
SimplifyTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify:To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify:To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrtTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrtTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 -To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}) To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}). To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}) 7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}). 6To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}) 7.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}). 6.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
FurtherTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
FurtherTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplifyTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplifyTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \fracTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrtTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrtTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}) To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}). To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}) 8.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}). 7.To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
SinceTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(xTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x =To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \fracTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}})To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pmTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) isTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not aTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfectTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\sqrtTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfect squareTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\sqrt{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfect square,To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\sqrt{5To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfect square, theTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\sqrt{5}}}{{To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfect square, the expression cannotTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\sqrt{5}}}{{2}}To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfect square, the expression cannot beTo solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\sqrt{5}}}{{2}})To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfect square, the expression cannot be simplified further. To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0)
-
Combine like terms: (x^2 - 7x + 1 = 0)
-
Identify the coefficients: (a = 1), (b = -7), (c = 1)
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}})
-
Plug in the coefficients: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}})
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}})
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}})
-
(x = \frac{{7 \pm 3\sqrt{5}}}{{2}})To solve the equation (x^2 - 3x = 4x - 1) using the quadratic formula:
-
Rewrite the equation in standard form: (x^2 - 3x - 4x + 1 = 0), which simplifies to (x^2 - 7x + 1 = 0).
-
Identify the coefficients: (a = 1), (b = -7), and (c = 1).
-
Apply the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}).
-
Substitute the coefficients into the formula: (x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(1)(1)}}}}{{2(1)}}).
-
Simplify: (x = \frac{{7 \pm \sqrt{{49 - 4}}}}{{2}}).
-
Further simplify: (x = \frac{{7 \pm \sqrt{{45}}}}{{2}}).
-
Since (\sqrt{{45}}) is not a perfect square, the expression cannot be simplified further.
-
The solutions are (x = \frac{{7 + \sqrt{{45}}}}{{2}}) and (x = \frac{{7 - \sqrt{{45}}}}{{2}}), or approximately (x \approx 6.32) and (x \approx 0.68).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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