# How do you solve #(x +2) / 3 = 6/ (x-1)#?

By signing up, you agree to our Terms of Service and Privacy Policy

To solve the equation (x + 2) / 3 = 6 / (x - 1), you can start by cross-multiplying to eliminate the fractions. This gives you (x + 2)(x - 1) = 18. Expanding the left side of the equation, you get x^2 + x - 2 = 18. Rearranging the equation, you have x^2 + x - 20 = 0. Factoring the quadratic equation, you find (x + 5)(x - 4) = 0. Therefore, the solutions are x = -5 and x = 4.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you solve rational equations #[(x+2) / (x-1)] = [1/2]#?
- How do you graph and find the discontinuities of #(x^(1/2) +1)/(x+1) #?
- How do you divide #(6x^3-12x^2-5x+3) / (6x-9)# using long division?
- How do you simplify #(3x-2)/(6x) + (5x+1)/(9x)#?
- How do you solve #1/x+2/(3x)=1/3# and find any extraneous solutions?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7