How do you solve #(x +2) / 3 = 6/ (x-1)#?

Answer 1
#(x+2) / 3 = 6/(x-1)#
cross multiplying: #(x+2)(x-1) = 6.3#
# x^2 -x +2x - 2 = 18# # x^2 + x - 20=0#
Factorising by splitting the middle term: # x^2 + 5x - 4x - 20=0# # x(x+5) - 4 (x+5)=0# # (x- 4) (x+5)=0#
the solutions for the expression are: #color(blue)(x=4 , x=-5#
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Answer 2

To solve the equation (x + 2) / 3 = 6 / (x - 1), you can start by cross-multiplying to eliminate the fractions. This gives you (x + 2)(x - 1) = 18. Expanding the left side of the equation, you get x^2 + x - 2 = 18. Rearranging the equation, you have x^2 + x - 20 = 0. Factoring the quadratic equation, you find (x + 5)(x - 4) = 0. Therefore, the solutions are x = -5 and x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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