How do you solve # x^2+3=0#?

Answer 1

Put all the variables on one side of the equal sign, then solve from there.

You want to get all the variables over to one side, so subtract 3 over to the right side. You should then get #x^2=-3#.

You'd then square root both sides to get the simplified version of x.

#sqrt(x^2)=sqrt(-3)#
The square root of #x^2# is simply x, but the #sqrt(-3)# is more complicated, as you can't get the square root of a negative number. You'd have to involve #i#, or the idea of an imaginary number.
(Right now, we have #x=sqrt(-3)#
Because #i=sqrt(-1)#, we could multiply our 3 and #i#. If #sqrt(-3) = 3*sqrt(-1) = 3i#, then #x=3i#.
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Answer 2

To solve the equation (x^2 + 3 = 0), you can subtract 3 from both sides of the equation to isolate (x^2), then take the square root of both sides to solve for (x). However, since the square root of a negative number is not real, this equation has no real solutions. The solutions will involve imaginary numbers. Therefore, the solutions to (x^2 + 3 = 0) are complex numbers and can be expressed as (x = \pm \sqrt{-3}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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