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How do you solve #x^2-2x=0 #?

Answer 1

Hazel Anglin

#x=0, x=2#

#x^2-2x=0#

#x# is common to both terms of the L.H.S:

#color(blue)(x) color(green)( (x-2))=0#

Equating both factors to zero to obtain the values of #x#: 1) #color(blue)(x)=0#

2) #color(green)( x-2) = 0 , x=2#

The values for #x# are : #x=0, x=2#

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Answer 2

Avery Alexander

To solve (x^2 - 2x = 0), you factor out the common term (x), giving you (x(x - 2) = 0). Then, you apply the zero-product property, setting each factor equal to zero: (x = 0) and (x - 2 = 0). Solve for (x) in each equation to get (x = 0) and (x = 2). So, the solutions are (x = 0) and (x = 2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.