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How do you solve #x^2 = 256#?

Answer 1

Genesis Allen

You just take the square root of both sides. Square root of #x^2# would give you an x. #sqrt(256)# would give you 16.

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Answer 2

Kennedy Adams

This has two solutions #x=16# and #x=-16#

Finding the square roots of a number can be done in part by factorizing it first.

In this example, #256# is obviously even, so divide it by #2# to find:

#256 = 2 * 128#

Then #128# is even, so divide that by #2# to find:

#256 = 2 * 2 * 64#

Proceed until you come across:

#256 = 2*2*2*2*2*2*2*2 = 2^8#

As of right now, it's evident that:

#256 = (2*2*2*2)*(2*2*2*2) = 2^4*2^4 = (2^4)^2 = 16^2#

So #16# is a solution, but #-16# is also a solution since:

#(-16)^2 = (-16)*(-16) = 256#

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Answer 3

Abigail Allen

To solve the equation ( x^2 = 256 ), you can take the square root of both sides. Since the square root of 256 is 16, the solutions are ( x = 16 ) and ( x = -16 ).

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Answer 4

Jameson Allen

To solve ( x^2 = 256 ), you take the square root of both sides. This gives you:

[ x = \pm \sqrt{256} ]

[ x = \pm 16 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.