How do you solve #x^2 - 25 = 0#?

Answer 1

#x_1=+5#
#x_2=-5#

Take #25# to the right: #x^2=25# square root both sides to get: #x=+-sqrt(25)# So you get two possible solutions: #x_1=+5# #x_2=-5#

You can also use the Quadratic Formula but this is faster.

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Answer 2

To solve x^2 - 25 = 0, you can use the difference of squares formula, which states that a^2 - b^2 = (a + b)(a - b).

So, you rewrite the equation as:

x^2 - 25 = (x + 5)(x - 5)

To find the solutions, set each factor equal to zero:

x + 5 = 0 or x - 5 = 0

Solve for x:

For x + 5 = 0: x = -5

For x - 5 = 0: x = 5

Therefore, the solutions to the equation x^2 - 25 = 0 are x = -5 and x = 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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