How do you solve #(x-2)^2-25=0#?
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add 25 to both sides.
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To solve the equation (x-2)^2 - 25 = 0, first expand the squared term: (x - 2)(x - 2) - 25 = 0 x^2 - 4x + 4 - 25 = 0 x^2 - 4x - 21 = 0 Next, use the quadratic formula to find the solutions for x: x = [ -(-4) ± √((-4)^2 - 4(1)(-21)) ] / (2*1) x = [ 4 ± √(16 + 84) ] / 2 x = [ 4 ± √(100) ] / 2 x = [ 4 ± 10 ] / 2 This yields two possible solutions: x1 = (4 + 10) / 2 = 14 / 2 = 7 x2 = (4 - 10) / 2 = -6 / 2 = -3 Therefore, the solutions to the equation (x-2)^2 - 25 = 0 are x = 7 and x = -3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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