How do you solve #x^2-2=17#?

Answer 1

See the entire solution process below:

First, add #color(red)(2)# to each side of the equation to isolate #x^2# while keeping the equation balanced:
#x^2 - 2 + color(red)(2) = 17 + color(red)(2)#
#x^2 - 0 = 19#
#x^2 = 19#
Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Also remember, the square root of a number has both a negative and positive answer:
#sqrt(x^2) = +-sqrt(19)#
#x = +-sqrt(19) = +-4.359# rounded to the nearest thousandth.
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Answer 2

To solve the equation (x^2 - 2 = 17), you would first add 2 to both sides of the equation to isolate the (x^2) term. This gives you (x^2 = 19). Then, you would take the square root of both sides to solve for (x). However, it's important to consider both the positive and negative square roots, so the solutions are (x = \sqrt{19}) and (x = -\sqrt{19}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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