How do you solve #x^2-18x=-32#?
Start by turning it into a quadratic equation in standard form...
...by adding 32 to both sides. You then have:
...so then you can see that if x = 2 or x = 16, then the equation is true.
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To solve the equation (x^2 - 18x = -32), follow these steps:
- Rewrite the equation in standard form: (x^2 - 18x + 32 = 0).
- Factor the quadratic expression or use the quadratic formula.
- If factoring is possible, factor the expression and solve for (x). If factoring is not possible, use the quadratic formula: [x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}] where (a = 1), (b = -18), and (c = 32).
- Plug the values of (a), (b), and (c) into the quadratic formula and simplify to find the solutions for (x).
- The solutions may be real or complex numbers.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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