How do you solve #x^2-18x=-32#?

Answer 1

Start by turning it into a quadratic equation in standard form...

...by adding 32 to both sides. You then have:

#x^2 - 18x + 32 = 0#
And then you might be able to factor it directly. By noting that #-2 * -16 = 32# and #-2 - 16 = -18#
#(x - 2)(x-16) = 0#

...so then you can see that if x = 2 or x = 16, then the equation is true.

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Answer 2

To solve the equation (x^2 - 18x = -32), follow these steps:

  1. Rewrite the equation in standard form: (x^2 - 18x + 32 = 0).
  2. Factor the quadratic expression or use the quadratic formula.
  3. If factoring is possible, factor the expression and solve for (x). If factoring is not possible, use the quadratic formula: [x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}] where (a = 1), (b = -18), and (c = 32).
  4. Plug the values of (a), (b), and (c) into the quadratic formula and simplify to find the solutions for (x).
  5. The solutions may be real or complex numbers.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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