How do you solve #x^2 + 16x = -64#?
x = -8
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To solve the equation ( x^2 + 16x = -64 ), follow these steps:
- Rewrite the equation in standard quadratic form: ( x^2 + 16x + 64 = 0 ).
- Factor the quadratic expression: ( (x + 8)^2 = 0 ).
- Take the square root of both sides: ( x + 8 = 0 ).
- Solve for ( x ): ( x = -8 ).
Therefore, the solution to the equation is ( x = -8 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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