# How do you solve #x^2 + 16x = 0# by completing the square?

#(x+8)^2 = 64

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To solve the equation x^2 + 16x = 0 by completing the square, follow these steps:

- Move the constant term to the other side of the equation: x^2 + 16x = 0 becomes x^2 + 16x - 0 = 0.
- Identify the coefficient of x, which is 16.
- Divide the coefficient of x by 2 and square the result: (16/2)^2 = 64.
- Add the result from step 3 to both sides of the equation: x^2 + 16x + 64 = 64.
- Factor the perfect square trinomial on the left side: (x + 8)^2 = 64.
- Take the square root of both sides: x + 8 = ±√64.
- Solve for x: x + 8 = ±8.
- Subtract 8 from both sides: x = -8 ± 8.
- Simplify: x = -8 + 8 or x = -8 - 8.
- Solve for x: x = 0 or x = -16.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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