How do you solve #x^2+15x=0#?

Answer 1

#color(blue)(x=0)# or #color(blue)(x=-15)#

Factoring #x^2+15x=0# gives #color(white)("XX")x(x+15)=0#
which implies either #color(white)("XX")x=0# or #color(white)("XX")(x+15=0)# #color(white)("XXXXX")rarr x=-15#
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Answer 2

#x= 0, or x = -15#

The first approach is always to try and factorise the quadratic. Although this is not a trinomial, there is a common factor.

#x(x+15)=0#

Because the product is 0, one of the two factors must be equal to 0.

Either #x = 0, or x+ 15 =0," in which case " x = -15#

This gives two solutions, exactly what we expect with a quadratic.

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Answer 3

To solve the quadratic equation (x^2 + 15x = 0), we can factor out an (x) from the left side:

(x(x + 15) = 0)

Now, we have a product of two factors equal to zero. According to the zero product property, if the product of two factors is zero, then at least one of the factors must be zero. So, we set each factor to zero and solve for (x):

(x = 0) or (x + 15 = 0)

Solving (x + 15 = 0) for (x), we get:

(x = -15)

Therefore, the solutions to the equation (x^2 + 15x = 0) are (x = 0) and (x = -15).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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