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How do you solve #x^2 + 15 =0#?

Answer 1

Eli Assouline

In the set of real numbers, it does not have any solutions.

In the complex numbers it is

#x^2+15=0=>x^2=15i^2=>x=+-sqrt15i#

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Answer 2

Savannah Anderson

To solve the equation (x^2 + 15 = 0), you would first subtract 15 from both sides to isolate (x^2). Then, you would take the square root of both sides and consider both the positive and negative roots. So, (x^2 = -15), implies (x = \pm \sqrt{-15}). However, (\sqrt{-15}) is not a real number since the square root of a negative number is imaginary. Therefore, the equation has no real solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.