How do you solve #x^2 = 14x – 49#?

Answer 1

Eli Assouline

The answer is #x = 7#.

#x^2=14x-49#

Subtract #14x# from both sides of the equation.

#x^2-14x=-49#

Add #49# to both sides of the equation.

#x^2-14x+49=0#

#x^2-14x+49# is a perfect square trinomial in the form #a^2+2ab+b^2=(a+b)^2#, where #a=x and b=-7#.

#x^2-14x+49=0# =

#(x-7)^2=0#

Take the square root of both sides.

#(x-7)=sqrt 0# =

#x-7=0# =

#x=7#

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Answer 2

Jace Anderson

To solve the equation (x^2 = 14x - 49), follow these steps:

Move all terms to one side to set the equation to zero: (x^2 - 14x + 49 = 0).
Factor the quadratic equation: ((x - 7)^2 = 0).
Take the square root of both sides: (x - 7 = 0).
Add 7 to both sides: (x = 7).

So, the solution to the equation is (x = 7).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.