How do you solve #x^2+14x + 49= 19#?
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To solve the equation (x^2 + 14x + 49 = 19), follow these steps:

Subtract 19 from both sides of the equation: (x^2 + 14x + 49  19 = 0) (x^2 + 14x + 30 = 0)

Rewrite the equation in the standard quadratic form: (x^2 + (10x + 4x) + 30 = 0)

Factor the quadratic expression: ((x + 10)(x + 3) = 0)

Set each factor equal to zero and solve for (x): (x + 10 = 0 \Rightarrow x = 10) (x + 3 = 0 \Rightarrow x = 3)
Therefore, the solutions to the equation are (x = 10) and (x = 3).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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