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How do you solve #x^2=13x-42#?

Answer 1

Avery Alexander

The roots of #x# are #7# and #6#

This formula can be expressed as

#x^2-13x+42=0#

#x^2-7x-6x+42 =0#

#x(x-7)-6(x-7)=0#

#(x-7)(x-6)=0#

So #x-7=0# or #x-6=0#

therefore #x=7# or #6# [answer]

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Answer 2

Nathan Axel

To solve the equation (x^2 = 13x - 42), follow these steps:

Move all terms to one side to set the equation to zero: (x^2 - 13x + 42 = 0).
Factorize the quadratic equation: (x^2 - 13x + 42 = (x - 6)(x - 7) = 0).
Set each factor equal to zero and solve for (x):
- For (x - 6 = 0), (x = 6).
- For (x - 7 = 0), (x = 7).
The solutions to the equation are (x = 6) and (x = 7).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.