How do you solve #x^2-12x+20=0# by completing the square?
First, enter your quadratic in the appropriate form.
This allows us to write the left side of the equation as
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Get the answer by taking the square root of each side of the equation.
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To solve the quadratic equation (x^2 - 12x + 20 = 0) by completing the square, follow these steps:
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Move the constant term to the other side of the equation: (x^2 - 12x = -20)
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To complete the square, halve the coefficient of (x), square it, and add it to both sides of the equation: Add ((\frac{12}{2})^2 = 36) to both sides: (x^2 - 12x + 36 = -20 + 36)
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Simplify: ((x - 6)^2 = 16)
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Take the square root of both sides: (x - 6 = \pm \sqrt{16})
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Solve for (x): (x - 6 = \pm 4) (x = 6 \pm 4)
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Simplify: (x = 10) or (x = 2)
So, the solutions to the equation (x^2 - 12x + 20 = 0) by completing the square are (x = 10) and (x = 2).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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