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How do you solve x-(12-x)=38#?

Answer 1

Eva Abramson

#x=25#

#x-12+x=38# #x+x=38+12# #2x=50# #x=25#

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Answer 2

Savannah Anderson

#x=25#

We start with #x-(12-x)=38#

Now, I like to begin by simplifying everything I can, and then combining like terms to reduce it down to its most concise form. In this case, I'm going to get rid of the parentheses.

So, we have #-(12-x)#. The #-# in front of the parentheses is actually a #-1#, and we will distribute the #-1# into #(12-x)#. It is now #((12*-1)-(x*-1))#, or #-12--x#, which is just #-12+x#.

The equation is now #x-12+x=38#. We can add #12# to both sides and combine the #x#s until we have #2x=50#.

Divide by #2# on both sides as we have #x=25#!

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Answer 3

Avery Alexander

To solve the equation x - (12 - x) = 38, first distribute the negative sign inside the parentheses:

x - 12 + x = 38

Combine like terms:

2x - 12 = 38

Add 12 to both sides:

2x = 50

Divide both sides by 2:

x = 25

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.