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How do you solve #x+12>2x-5#?

Answer 1

Eva Adamson

See below

#-x#:

#12>x-5#

#+5#

#17>x#

This can be written as:

#x<17# graph{x<17 [-46.17, 46.32, -23.1, 23.12]}

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Answer 2

Eli Assouline

To solve the inequality (x + 12 > 2x - 5), we need to isolate (x) on one side of the inequality sign.

Subtract (x) from both sides: [12 > x - 5]
Add 5 to both sides: [17 > x]

So, the solution to the inequality is (x < 17).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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How do you solve #x+12&gt;2x-5#?

How do you solve #x+12>2x-5#?