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How do you solve #(x+1)/3 = (x-1)/4#?

Answer 1

Julia Adams

x=-7

4(x+1) = 3(x-1) 4x+4 = 3x-3 4x-3x = -4-3 x = -7

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Answer 2

Isaiah Anthony

#x=-7#

In the equation #(x+1)/3=(x-1)/4#, let us first multiply both sides by LCD of #3# and #4# i.e. #12# to eliminate fractions.

Thus, this formula can be expressed as

#(x+1)/3xx12=(x-1)/4xx12#

#4(x+1)=3(x-1)# or

#4x+4=3x-3#

now transposing terms containing variable #x# to left hand side and constant terms to right hand side, we get

#4x-3x=-3-4# or

#x=-7#

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Answer 3

Isaiah Anthony

To solve the equation (x+1)/3 = (x-1)/4, you can cross-multiply to eliminate the fractions. Multiply both sides of the equation by the denominators, which are 3 and 4 respectively. This will give you 4(x+1) = 3(x-1). Distribute the multiplication on both sides of the equation. Simplify the equation by expanding the brackets. Collect like terms by combining the x terms and the constant terms separately. Finally, solve for x by isolating it on one side of the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.