Home > Algebra > Use Square Roots to Solve Quadratic Equations

How do you solve # (x+1)^2-3=13#?

Answer 1

#x = 3 or x = -5#

Although this is a quadratic equation, we do not have to use the normal method of making it equal to 0. This is a special case - there is no x-term.

Move all the constants to the right hand side and then find the square root of each side.

#(x+1)^2 = 16#

#x+1 = +-sqrt16 = +-4#

#if x+1 =+4 " " rarr x = 3#

#if x+1 = -4" " rarr x = -5#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Avery Alexander

To solve ( (x+1)^2 - 3 = 13 ), first, add 3 to both sides to isolate ( (x+1)^2 ). Then, take the square root of both sides. Finally, solve for ( x ). So, the solution is ( x = \pm \sqrt{16} - 1 ), which simplifies to ( x = 3 ) or ( x = -5 ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.