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How do you solve #w(4w+6)+2w=2(2w^2+7w-3)#?

Answer 1

Ethan Adkins

#w = 1#

#w(4w + 6) + 2w = 2(2w^2 + 7w - 3)#

Use the Distributive Property: #w(4w + 6) + 2w = 2(2w^2 + 7w - 3)# #4w^2 + 6w + 2w = 4w^2 + 14w - 6#

Combine Like Terms: #4w^2 + 6w + 2w = 4w^2 + 14w - 6# #4w^2 + 8w = 4w^2 + 14w - 6#

Use the Additive Inverse: #4w^2 + 8w = 4w^2 + 14w - 6# #8w = 14w - 6# #-6x = -6# #w = 1#

There's your answer!

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Answer 2

Jace Anderson

To solve the equation (w(4w+6)+2w=2(2w^2+7w-3)):

Distribute (w) into (4w+6) to get (4w^2 + 6w).
Combine like terms to get (4w^2 + 6w + 2w).
Combine like terms on the right side to get (4w^2 + 6w + 2w = 4w^2 + 14w - 6).
Set the left side equal to the right side to form (4w^2 + 8w = 4w^2 + 14w - 6).
Subtract (4w^2) from both sides to get (8w = 14w - 6).
Subtract (14w) from both sides to get (-6w = -6).
Divide both sides by (-6) to solve for (w): (w = 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.