# How do you solve using the completing the square method # x(x - 2) = 5#?

We begin with the provided equation.

To make it a trinomial, expand it.

Calculate the square roots of the equation's two sides.

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To solve the equation x(x - 2) = 5 using the completing the square method:

- Expand the expression x(x - 2) to get x^2 - 2x.
- Rearrange the equation to have the terms on one side equal to zero: x^2 - 2x - 5 = 0.
- To complete the square, take half of the coefficient of x, square it, and add it to both sides of the equation.
- Half of -2 is -1, and (-1)^2 equals 1. Add 1 to both sides: x^2 - 2x + 1 = 5 + 1.
- Factor the left side as a perfect square trinomial: (x - 1)^2 = 6.
- Take the square root of both sides: x - 1 = ±√6.
- Add 1 to both sides to isolate x: x = 1 ± √6.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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