How do you solve using the completing the square method #x^2  30x = 125#?
Now write the left hand side as a perfect square and simplify the right hand side.
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To solve the equation (x^2  30x = 125) using the completing the square method, follow these steps:

Move the constant term to the right side of the equation: (x^2  30x + 125 = 0)

Add and subtract the square of half the coefficient of the linear term (in this case, (15^2 = 225)): (x^2  30x + 225 + 125 = 225)

Factor the perfect square trinomial: ((x  15)^2 = 225)

Take the square root of both sides and solve for (x): (x  15 = \pm \sqrt{225}) (x  15 = \pm 15)

Solve for (x): (x = 15 \pm 15) (x = 15 + 15) or (x = 15  15)

Simplify: (x = 30) or (x = 0)
So, the solutions are (x = 30) or (x = 0).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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