How do you solve using the completing the square method #-2x^2 - 7x + 4#?
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To solve the quadratic equation -2x^2 - 7x + 4 using the completing the square method, follow these steps:
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First, ensure that the coefficient of the x^2 term is 1. Since the coefficient is already -2, divide the entire equation by -2 to get x^2 + (7/2)x - 2.
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Rewrite the equation in the form (x + p)^2 + q, where p is half the coefficient of x and q is the constant term.
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In this case, p = (7/2) / 2 = 7/4 and q = -2.
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Rewrite the equation as (x + 7/4)^2 - 2.
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Expand (x + 7/4)^2 to get x^2 + (7/2)x + (49/16).
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Rewrite the equation as x^2 + (7/2)x + (49/16) - (32/16).
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Combine the terms to get x^2 + (7/2)x + (17/16).
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The vertex form of the quadratic equation is (x + 7/4)^2 - 17/16.
Therefore, the solutions for the equation -2x^2 - 7x + 4 using the completing the square method are x = (-7 ± √17)/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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