How do you solve using completing the square method #x^2  4x = 5#?
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To solve the equation x^2  4x = 5 using the completing the square method, follow these steps:

Move the constant term to the other side of the equation: x^2  4x  5 = 0

To complete the square, take half of the coefficient of x (4 in this case), square it, and add it to both sides of the equation: x^2  4x + (4/2)^2 = 5 + (4/2)^2 x^2  4x + 4 = 5 + 4 x^2  4x + 4 = 9

Factor the left side of the equation, which is now a perfect square trinomial: (x  2)^2 = 9

Take the square root of both sides of the equation: x  2 = ±3

Solve for x: x = 2 ± 3 x = 2 + 3 or x = 2  3 x = 5 or x = 1
So, the solutions to the equation x^2  4x = 5 are x = 5 and x = 1.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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