# How do you solve #u(u - 5) + 8u = u(u + 2) - 4 #?

See a solution process below:

Initially, multiply each term inside the parenthesis by the term outside the parenthesis to expand the terms in parenthesis on each side of the equation:

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To solve the equation ( u(u - 5) + 8u = u(u + 2) - 4 ), first distribute and combine like terms:

( u^2 - 5u + 8u = u^2 + 2u - 4 )

( u^2 + 3u = u^2 + 2u - 4 )

Subtract ( u^2 ) from both sides:

( 3u = 2u - 4 )

Subtract ( 2u ) from both sides:

( u = -4 )

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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