How do you solve this chemical equation: Propanone to 2-bromopropane using L, M and reagents in 3 step process?

Answer 1

Why don't you just buy the alkyl halide......?

If that doesn't work.....

#H_3C-C(=O)CH_3stackrel(NaBH_4)rarrH_3C-CH(OH)CH_3#
#H_3C-CH(OH)CH_3stackrel(H_3PO_4"/"Delta)rarrH_2C=CHCH_3 + H_2O#
#H_2C=CHCH_3 stackrel(HBr)rarrH_3C-CHBrCH_3#

That's a lot of work for something you can buy for peanuts—three steps.

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Answer 2
  1. First, use L (Lewis acid), M (nucleophile), and the appropriate reagents to convert propanone to propene.
  2. Next, use L (catalyst) and the appropriate reagents to add bromine to propene to form 2-bromopropane.
  3. Finally, purify and isolate 2-bromopropane to obtain the desired product.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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