# How do you solve the system of equations #-16x - 4y = 12# and #- 4x + y = - 11#?

Given 2 equations, let us number them

the two equations are:

therefore,x=1 and y=-7#

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To solve the system of equations ( -16x - 4y = 12 ) and ( -4x + y = -11 ), you can use the method of substitution or elimination. Let's use the substitution method here:

First, solve the second equation for y: [ -4x + y = -11 ] [ y = -11 + 4x ]

Now substitute this value of y into the first equation: [ -16x - 4(-11 + 4x) = 12 ] [ -16x + 44 - 16x = 12 ]

Combine like terms: [ -32x + 44 = 12 ]

Subtract 44 from both sides: [ -32x = -32 ]

Divide by -32: [ x = 1 ]

Now substitute the value of x back into the second equation to find y: [ y = -11 + 4(1) ] [ y = -11 + 4 ] [ y = -7 ]

So the solution to the system of equations is ( x = 1 ) and ( y = -7 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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