# How do you solve the system by graphing #4x - 2y = -12# and #2x + y = -2#?

In this case, I have plotted the functions on the same plane.

graph{(4x-2y+12)(2x+y+2)=0 [-7.9, 7.9, -3.94, 3.96]}

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To solve the system by graphing, first graph each equation on the same coordinate plane. Then, find the point where the two lines intersect, which represents the solution to the system. In this case, the solution is the point where the graphs of the lines 4x - 2y = -12 and 2x + y = -2 intersect.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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