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How do you solve the system #9a+2b=10# and #9a-2b=10#?

Answer 1

Abigail Allen

#a=10/9#
#b=0#

I would add the two equation together as: #{9a+2b=10# #{9a-2b=10# #----=-# #18a+//=20#

So that #a=20/18=10/9# and using this value into the first equation: #9*10/9+2b=10# #b=0#

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Answer 2

Jameson Allen

To solve the system of equations 9a + 2b = 10 and 9a - 2b = 10, you can use the method of elimination. Add the two equations together:

(9a + 2b) + (9a - 2b) = 10 + 10

This simplifies to:

18a = 20

Now, divide both sides by 18 to solve for 'a':

a = 20/18

Simplify:

a = 10/9

Now that we have found the value of 'a', substitute it back into one of the original equations to solve for 'b'. Let's use the first equation:

9a + 2b = 10

Substitute 'a = 10/9':

9(10/9) + 2b = 10

This simplifies to:

10 + 2b = 10

Subtract 10 from both sides:

2b = 0

Now, divide both sides by 2:

b = 0

So, the solution to the system of equations is 'a = 10/9' and 'b = 0'.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.