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How do you solve the system #3x − 6y = 3# and #7x − 5y = −11 #?

Answer 1

Kennedy Adams

Try this:

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Answer 2

Eva Abramson

(1) 15x - 30y = 15 —-> Multiply by 5 -> 3x - 6y = 3.

(2) Multiply by -6 to get 42x + 30y = -66 from 7x - 5y = -11.

Add (1) and (2) -> 57x = -51 -># x = -51/57 = -17/19#

6y = 3x - 3 = 3(x - 1) = 3(-36/19) = -108/19 -># y = -108/114.#

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Answer 3

Genesis Allen

To solve the system 3x - 6y = 3 and 7x - 5y = -11:

Use one of the equations to solve for one variable in terms of the other.
Substitute the expression found in step 1 into the other equation.
Solve the resulting equation for the remaining variable.
Once you have found the value of one variable, substitute it back into one of the original equations to find the value of the other variable.
Verify the solution by substituting the values of x and y into both equations to ensure they satisfy both equations simultaneously.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.