How do you solve the system #2x+7y=3 # and #x = 1-4y# by substitution?
Subtract #3 from both sides to get:
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Try this:
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To solve the system using substitution, substitute the value of x from the second equation into the first equation.
From x = 1 - 4y, substitute x = 1 - 4y into the equation 2x + 7y = 3:
2(1 - 4y) + 7y = 3
Now, solve for y:
2 - 8y + 7y = 3
- y = 1 y = -1
Next, substitute y = -1 into x = 1 - 4y:
x = 1 - 4(-1) x = 1 + 4 x = 5
Therefore, the solution to the system is x = 5 and y = -1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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