How do you solve the rational equation # (x-3)/(x+1)=(x-6)/(x+5)#?
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To solve the rational equation (x-3)/(x+1)=(x-6)/(x+5), you can start by cross-multiplying to eliminate the fractions. This gives you (x-3)(x+5) = (x-6)(x+1). Expanding both sides of the equation, you get x^2 + 2x - 15 = x^2 - 5x - 6. Simplifying further, you have 7x = -9. Dividing both sides by 7, the solution is x = -9/7.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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