How do you solve the rational equation # (x-3)/(x+1)=(x-6)/(x+5)#?

Answer 1

I found: #x=9/7#

I would get rid of the denominators changing side and multiplying: #(x-3)(x+5)=(x-6)(x+1)# #cancel(x^2)+5x-3x-15=cancel(x^2)+x-6x-6# #2x-15=-5x-6# #7x=9# #x=9/7#
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Answer 2

To solve the rational equation (x-3)/(x+1)=(x-6)/(x+5), you can start by cross-multiplying to eliminate the fractions. This gives you (x-3)(x+5) = (x-6)(x+1). Expanding both sides of the equation, you get x^2 + 2x - 15 = x^2 - 5x - 6. Simplifying further, you have 7x = -9. Dividing both sides by 7, the solution is x = -9/7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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