How do you solve the inequality #-x^2 - x + 6 <0#?

Answer 1

#x< -3" or "x>2#

#"factor the quadratic"#
#-(x^2+x-6)<0#
#rArr-(x+3)(x-2)<0#
#"find the zeros by solving"#
#(x+3)(x-2)=0#
#rArrx=-3" or "x=2#
#"since the coefficient of "x^2" term "<0rArrnnn#
#rArrx< -3" or "x>2# graph{-x^2-x+6 [-10, 10, -5, 5]}
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Answer 2

To solve the inequality ( -x^2 - x + 6 < 0 ), first, factor the quadratic expression. Then, determine the critical points by setting each factor equal to zero and solving for ( x ). After finding the critical points, test intervals between the critical points by choosing test points in each interval and checking whether they satisfy the inequality. Finally, express the solution set using interval notation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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