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How do you solve the inequality #x-2<=1# or #4x+3>=19#?

Answer 1

Savannah Anderson

#x<=3# or #x>=4#

Solve each inequality on its own:

#x-2<=1\rightarrow x<=3# (added 2 to both sides)

For the second inequality, start: #4x+3>=19#

Subtract 3 from both sides: #4x>=16#

Divide both sides by 4: #x>=4#

Our final answer is the combination of the two results we've found:

#x<=3# or #x>=4#

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Answer 2

Eva Abramson

To solve the inequality ( x - 2 \leq 1 ) or ( 4x + 3 \geq 19 ), we can solve each inequality separately:

For ( x - 2 \leq 1 ): ( x - 2 \leq 1 ) Add 2 to both sides: ( x \leq 3 )
For ( 4x + 3 \geq 19 ): ( 4x + 3 \geq 19 ) Subtract 3 from both sides: ( 4x \geq 16 ) Divide both sides by 4: ( x \geq 4 )

So, the solution to the inequality ( x - 2 \leq 1 ) or ( 4x + 3 \geq 19 ) is ( x \leq 3 ) or ( x \geq 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve the inequality #x-2&lt;=1# or #4x+3&gt;=19#?

How do you solve the inequality #x-2<=1# or #4x+3>=19#?