Home > Algebra > Multi-Step Inequalities

How do you solve the inequality #7+14x<21# or #8x>12#?

Answer 1

Eva Adamson

#x<1# or #x>3/2#

We will start by solving the first inequality, then the second, and comparing our answers to get a range for x.

#7+14x<21#
#1+2x<3#
#2x<2#
#x<1#

And the second:

#8x>12#
#x>12/8#
#x>3/2#

Comparing these:

#x<1# or #x>3/2#

See below the inequalities on a graph:

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Savannah Anderson

To solve the inequality 7 + 14x < 21 or 8x > 12, you'll need to solve each inequality separately and then consider their intersection. For the first inequality, 7 + 14x < 21: Subtract 7 from both sides: 14x < 14 Divide both sides by 14: x < 1 For the second inequality, 8x > 12: Divide both sides by 8: x > 12/8 x > 3/2 Now, considering the intersection of both inequalities: x < 1 or x > 3/2 This means that the solution set for the given compound inequality is all real numbers x such that x is less than 1 or x is greater than 3/2.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve the inequality #7+14x&lt;21# or #8x&gt;12#?

How do you solve the inequality #7+14x<21# or #8x>12#?