How do you solve the inequality #5q+7<=3(q+1)#?

Answer 1

Savannah Anderson

# q ≤ -2#

#5q + 7 ≤ 3(q + 1)#

#5q + 7 ≤ 3xxq + 3xx1#

#5q - 3q ≤ 3 - 7#

#2q ≤ -4#

# q ≤ -4/2#

# q ≤ -2#

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Answer 2

Avery Alexander

To solve the inequality 5q + 7 ≤ 3(q + 1), you first distribute the 3 on the right side of the equation to get rid of the parentheses. Then, you combine like terms and isolate the variable q. Finally, you determine the solution set by considering the inequality sign and any possible restrictions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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How do you solve the inequality #5q+7&lt;=3(q+1)#?

How do you solve the inequality #5q+7<=3(q+1)#?