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How do you solve the inequality #-5(k+ 4)>3(k-4)#?

Answer 1

k < - 1

first I'm going to reverse the inequality so that there is not a leading - sign. When this is done the inequality symbol must be reversed.

3(k - 4 ) < - 5(k + 4 )

now multiply out the brackets.

#rArr 3k - 12 < - 5k - 20 #

now collect like terms.

3k + 5k < - 20 + 12

# rArr 8k <-8 #

now divide both sides by 8.

# rArr k < - 1 #

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Answer 2

Jameson Allen

To solve the inequality -5(k + 4) > 3(k - 4), follow these steps:

Distribute the -5 and 3 across the parentheses: -5k - 20 > 3k - 12
Combine like terms on each side: -20 > 8k - 12
Add 12 to both sides: -8 > 8k
Divide both sides by 8 (remember to flip the inequality sign because you're dividing by a negative number): k < -1

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve the inequality #-5(k+ 4)&gt;3(k-4)#?

3(k - 4 ) < - 5(k + 4 )

How do you solve the inequality #-5(k+ 4)>3(k-4)#?