How do you solve the inequality 2x+11>5 and 10x-13<-13?

Answer 1
#2x+11>5#
#2x> -6#
#x> -3#
#10x-13< -13#
#10x<0#
#x<0#
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Answer 2

To solve the inequality (2x+11>5), first subtract 11 from both sides to get (2x > -6). Then, divide both sides by 2 to get (x > -3).

To solve the inequality (10x-13<-13), add 13 to both sides to get (10x < 0). Then, divide both sides by 10 to get (x < 0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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