# How do you solve the inequality #2| x -5| > 32#?

Solving an inequality involves finding all the possible values of x that satisfy the equation; in this example

Any modulus function can be solved in two different ways: one for each positive and negative modulus bit. This means that there are two solutions for every (linear) modulus equation.

You'll notice that changing the negative signs requires you to change the inequality's direction as well.

Plotting the modulus graph is another way to solve this graphically, but I always go with this approach because it's more involved and offers more room for error.

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To solve the inequality (2|x-5| > 32), you would first isolate the absolute value term by dividing both sides of the inequality by 2, then solve the resulting inequality in two cases: when (x-5) is positive and when (x-5) is negative.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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