How do you solve the inequality #10(x+2)>2(6-9x)#?

We must simply first the inequality, both the left and right side :)

using Distributive Property of Real Numbers:

then we must combine the same terms/like terms (Using the Golden Rule of Algebra) (Balancing the Equation) :)

reduce to lowest terms,

To solve the inequality ( 10(x + 2) > 2(6 - 9x) ), follow these steps:

1. Distribute the constants and variables: ( 10x + 20 > 12 - 18x )

2. Combine like terms: ( 10x + 18x > 12 - 20 )

3. Simplify: ( 28x > -8 )

4. Divide both sides by 28: ( x > -\frac{8}{28} )

5. Simplify the fraction: ( x > -\frac{2}{7} )

Therefore, the solution to the inequality is ( x > -\frac{2}{7} ).

To solve the inequality (10(x+2) > 2(6-9x)), follow these steps:

1. Distribute the constants outside the parentheses:

[ 10x + 20 > 12 - 18x ]

2. Gather like terms by adding (18x) to both sides and subtracting (20) from both sides:

[ 10x + 18x > 12 - 20 ]

[ 28x > -8 ]

3. Divide both sides by (28), ensuring to reverse the inequality sign since we are dividing by a negative number:

[ x < -\frac{8}{28} ]

4. Simplify the fraction:

[ x < -\frac{2}{7} ]

So, the solution to the inequality (10(x+2) > 2(6-9x)) is (x < -\frac{2}{7}).