How do you solve the following system: #x+y=4 , 3x + 4y = 11 #?
Given that
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To solve the system of equations (x + y = 4) and (3x + 4y = 11), you can use the substitution method or the elimination method. Here's how to solve it using the substitution method:
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Solve the first equation for one variable in terms of the other. In this case, solve (x + y = 4) for (x): (x = 4 - y).
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Substitute the expression for (x) into the second equation: (3(4 - y) + 4y = 11).
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Simplify and solve for (y): (12 - 3y + 4y = 11), (12 + y = 11), (y = 11 - 12), (y = -1).
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Substitute the value of (y) back into the first equation to solve for (x): (x + (-1) = 4), (x = 4 + 1), (x = 5).
So, the solution to the system of equations is (x = 5) and (y = -1).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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