How do you solve the following system: #x+y=4 , 3x + 4y = 11 #?

Answer 1

#x=5#, #y=-1#

Given that

#x+y=4\ .........(1)#
#3x+4y=11\ .........(2)#
Multiplying (1) by #3# & subtracting from (2) as follows
#3x+4y-3(x+y)=11-3\times 4#
#y=-1#
setting #y=-1# in (1), we get
#x=4-y=4-(-1)=5#
hence, the solution is #x=5# & #y=-1#
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Answer 2

To solve the system of equations (x + y = 4) and (3x + 4y = 11), you can use the substitution method or the elimination method. Here's how to solve it using the substitution method:

  1. Solve the first equation for one variable in terms of the other. In this case, solve (x + y = 4) for (x): (x = 4 - y).

  2. Substitute the expression for (x) into the second equation: (3(4 - y) + 4y = 11).

  3. Simplify and solve for (y): (12 - 3y + 4y = 11), (12 + y = 11), (y = 11 - 12), (y = -1).

  4. Substitute the value of (y) back into the first equation to solve for (x): (x + (-1) = 4), (x = 4 + 1), (x = 5).

So, the solution to the system of equations is (x = 5) and (y = -1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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