# How do you solve the following system using substitution?: #5x+2y=-4, -3x+y=20#

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The solutions are

The equations are

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To solve the system using substitution:

- Solve one of the equations for one variable in terms of the other variable.
- Substitute the expression found in step 1 into the other equation.
- Solve the resulting equation for the remaining variable.
- Once you have found the value of one variable, substitute it back into one of the original equations to find the value of the other variable.
- Verify the solution by substituting the values of the variables into both original equations.

Let's solve the system: Given equations:

- ( 5x + 2y = -4 )
- ( -3x + y = 20 )

From equation 2, solve for ( y ): ( y = 20 + 3x )

Substitute ( 20 + 3x ) for ( y ) in equation 1: ( 5x + 2(20 + 3x) = -4 )

Now, solve for ( x ): ( 5x + 40 + 6x = -4 ) ( 11x + 40 = -4 ) ( 11x = -44 ) ( x = -4 )

Now that we have found the value of ( x ), substitute it back into equation 2 to find ( y ): ( y = 20 + 3(-4) ) ( y = 20 - 12 ) ( y = 8 )

So, the solution to the system is ( x = -4 ) and ( y = 8 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you solve by substitution #3x + 2y = 11# and #x - 2 = -4y#?
- How do you solve y = 2x + 9 and 2x - y = -9?

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