How do you solve the following system of equations?: #x+y= -2 , x-2y=13#?
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since we have two unknowns we need minimum of two equations to solve for them , and we have that too
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To solve the system of equations:
- Choose one of the equations and solve for one variable in terms of the other variable.
- Substitute the expression obtained in step 1 into the other equation.
- Solve the resulting equation for the remaining variable.
- Once you find the value of one variable, substitute it back into one of the original equations to find the value of the other variable.
- Verify the solution by substituting both values into the other equation to ensure it holds true.
Given the system: x + y = -2 x - 2y = 13
From the first equation, solve for x: x = -2 - y
Substitute x = -2 - y into the second equation: (-2 - y) - 2y = 13
Solve for y: -2 - y - 2y = 13 -2 - 3y = 13 -3y = 15 y = -5
Substitute y = -5 into the first equation to find x: x + (-5) = -2 x - 5 = -2 x = -2 + 5 x = 3
Therefore, the solution to the system is x = 3 and y = -5.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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